A string of mass per unit length mu = 6 ...

A string of mass per unit length `mu = 6 × 10^(-3)` kg/m is fixed at both ends under the tension 540 N. If the string is in resonance with consecutive frequencies 420 Hz and 490 Hz. Then find the length of the string?

`8.1 m`

`5.1m`

`2.1m`

`1.1m`

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The correct Answer is:

`2.1m`

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