" (a) "(1)/(4)[[x],[y]]=[[3,4],[2,3]][[4],[2]]-:vec pi times pi times pi yvec x

The possible values of theta in (0,pi) such that sin (theta) + sin (4theta) + sin(7theta) = 0 are (1) (2pi)/9 , i/4 , (4pi)/9, pi/2, (3pi)/4 , (8pi)/9 (2) pi/4, (5pi)/12, pi/2 , (2pi)/3, (3pi)/4, (8pi)/9 (3) (2pi)/9, pi/4 , pi/2 , (2pi)/3 , (3pi)/4 , (35pi)/36 (4) (2pi)/9, pi/4, pi/2 , (2pi)/3 , (3pi)/4 , (8pi)/9

The possible values of theta in (0,pi) such that sin (theta) + sin (4theta) + sin(7theta) = 0 are (1) (2pi)/9 , i/4 , (4pi)/9, pi/2, (3pi)/4 , (8pi)/9 (2) pi/4, (5pi)/12, pi/2 , (2pi)/3, (3pi)/4, (8pi)/9 (3) (2pi)/9, pi/4 , pi/2 , (2pi)/3 , (3pi)/4 , (35pi)/36 (4) (2pi)/9, pi/4, pi/2 , (2pi)/3 , (3pi)/4 , (8pi)/9

The possible values of theta in (0,pi) such that sin (theta) + sin (4theta) + sin(7theta) = 0 are (1) (2pi)/9 , i/4 , (4pi)/9, pi/2, (3pi)/4 , (8pi)/9 (2) pi/4, (5pi)/12, pi/2 , (2pi)/3, (3pi)/4, (8pi)/9 (3) (2pi)/9, pi/4 , pi/2 , (2pi)/3 , (3pi)/4 , (35pi)/36 (4) (2pi)/9, pi/4, pi/2 , (2pi)/3 , (3pi)/4 , (8pi)/9

Draw the graph of y= sqrt(2) sin (x+ (pi)/(4)) for the values of x= 0 , (pi)/(4) , (pi)/(2) ,(3pi)/(4) in [(pi)/(4) ,(3pi)/(4)] and find the maximum value of y.

The possible values of theta in (0, pi) such that sin (theta) + sin (4 theta) + sin (7 theta) = 0 are (1) (2 pi) / (9), (i) / (4 ), (4 pi) / (9), (pi) / (2), (3 pi) / (4), (8 pi) / (9) (2) (pi) / (4), (5 pi ) / (12), (pi) / (2), (2 pi) / (3), (3 pi) / (4), (8 pi) / (9) (3) (2 pi) / (9 pi) ), (pi) / (4), (pi) / (2), (2 pi) / (3), (3 pi) / (4), (35 pi) / (36) (4) (2 pi ) / (9), (pi) / (4), (pi) / (2), (2 pi) / (3), (3 pi) / (4), (8 pi) / (9)

The range of the function f(x) = cot^(-1)log_(0.5) (x^4 -2x^(2) +3) is a) (0,pi) b) (0,3pi//4) c) [3pi//4,pi) d) [pi//2, 3pi//4]

Statement-I: If |vec(a).vec(b)|= |vec(a) xx vec(b)| then (vec(a), vec(b))= (pi)/(4) or (3pi)/(4) Statement-II: If vec(a).vec(b)= |vec(a) xx vec(b)| then (vec(a), vec(b))= (pi)/(4) or (3pi)/(4) Which of the above two statements are true?

1+sinx + sin^2(x) + .... = 4+2sqrt3, 0ltxltpi, x!=pi, then x = 1) (pi)/(3), (pi)/(4) 2) (pi)/(4), (pi)/(6) 3) (2 pi)/(5), (pi)/(6) 4) (pi)/(3), (2 pi)/(3)