" In a triangle "ABC" ,show that "s.sec(A)/(2)sec(B)/(2)sec(C)/(2)=2[(abc)/(sin A sin B sin C)]^((1)/(3))

Similar Questions

Explore conceptually related problems

For triangle ABC, show that: sin((A+B)/(2))-cos(C)/(2)=0

For triangle ABC prove that sec((A+B)/2)="cosec"C/2

For triangle ABC, show that "sin"(A+B)/2="cos"C/2

In any triangle ABC, show that: 2a sin((B)/(2))sin((C)/(2))=(b+c-a)sin((A)/(2))

In a triangle ABC, prove that :a sin((A)/(2)+B)=(b+c)sin((A)/(2))

In any triangle ABC, show that : 2a sin (B/2) sin (C/2)=(b+c-a) sin (A/2)

In any triangle ABC show that b^2sin2C+c^2sin 2B=abc/R

Delta ABC,abc sin((A)/(2))sin((B)/(2))sin((C)/(2))=

In any triangle ABC, prove that: (sin(B-C))/(sin(B+C))=(b^(2)-c^(2))/(a^(2))

For any triangle ABC, prove that sin(B-C)/sin(B+C)=(b^2-c^2)/(a^2)