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[1+a,1,1,],[1,+b,1,1],[1,1,1+c,1],[1,1,1...

[1+a,1,1,],[1,+b,1,1],[1,1,1+c,1],[1,1,1+c,1],[1,1,1,1+d]|=abcd[1+(1)/(a)+(1)/(b)+(1)/(c)+(1)/(d)]

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Prove that |(1+a,1,1),(1,1+b,1),(1,1,1+c)|=abc(1+(1)/(a)+(1)/(b)+(1)/(c)).

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If D=[[1,a,b],[1,b,c],[1,c,a]] , then [[a,b,c],[b,c,a],[1,1,1]] =

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