(Atom sin Question 1. Formula of refractive index of prism - Derive

Write the formula for the refractive index of the prism.

Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism of given prism. Then the angle of prism is ...... (sin 48^@36. = 0.75)

Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism of given prism. Then, the angle is prism is…. (sin 48^(@)36'=0.75)

Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism of given prism. Then, the angle is prism is…. (sin 48^(@)36'=0.75)

A thin prism P of refracting angle 3^(@) and refractive index . 1.5 is combined with another thin prism Q of refractive index 1.6 to produce dispersion without deviation. Then the angle of prism Q is

A thin prism P of refracting angle 3^(@) and refractive index . 1.5 is combined with another thin prism Q of refractive index 1.6 to produce dispersion without deviation. Then the angle of prism Q is