Explain the fallacy in the following:` -1=i.i=sqrt(-1).sqrt(-1)=sqrt((-1)(-1))=sqrt(1)=1`

Explain the fallacy : -1 =(i xx i)=sqrt(-1)xx sqrt(-1) = sqrt((-1)xx(-1))=sqrt(1) = 1 .

Explain the fallacy -1=ixxi=sqrt-1xxsqrt-1=sqrt((-1)xx(-1))=sqrt1=1.

sqrt((1+i)/(1-i))

sqrt((1+i)/(1-i))

[sqrt(1+sqrt(1+sqrt(1)))]^4

Evaluate the following: (sqrt(x+1)+sqrt(x-1))^(6)+(sqrt(x+1)-sqrt(x-1))^(6)

sqrt(-i) = (1-i)/sqrt2

(i)1/sqrt(2)+sqrt(3)+1/sqrt(2)

If sqrt(2)=1.414,sqrt(3)=1.732 , find the value of the following : (i)(sqrt(2)+1)/(sqrt(2)-1)" "(ii)(sqrt(3)-1)/(sqrt(3)+1)" "(iii)(2+sqrt(6))/(sqrt(2))

" 2.(i) sqrt(3x+1)-sqrt(x-1)=2