If ` sqrt(a)+ib =x+iy ` prove that ` sqrt(a)-ib =x-iy`

If sqrt(a+ib)=x+iy then prove that sqrt(a-ib)=x-iy

If root(3)(a+ib) = x + iy, prove that : root(3)(a-ib) = x- iy .

If sqrt(a+ib)=x+iy , then value of sqrt(a-ib) is:

If sqrt(a+ib)=x+iy, then possible value of sqrt(a-ib) is x^(2)+y^(2) b.sqrt(x^(2)+y^(2)) c.x+iydx-iy e.sqrt(x^(2)-y^(2))

If (a+ib)/(c+id)=x+iy, prove that (a-ib)/(c-id)=x-iy and (a^(2)+b^(2))/(c^(2)+d^(2))=x^(2)+y^(2)

If (a+ib)/(c+id)=x+iy, prove that(i) (a-ib)/(c-id)=(x-iy)( ii) (a^(2)+b^(2))/(c^(2)+d^(2))=(x^(2)+y^(2))

If 1+4sqrt(3)i=(1+ib)^(2) , prove that: a^(2)-b^(2)=1 and ab=2sqrt(3) .

If x-iy=sqrt((a-ib)/(c-id)) then prove that x^(2)+y^(2)=(a^(2)+b^(2))/(c^(2)+d^(2))

If (x+iy)=sqrt((a+ib)/(c+id)) then prove that (x^(2)+y^(2))^(2)=(a^(2)+b^(2))/(c^(2)+d^(2))