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If A=[(1,1,1),(1,1,1),(1,1,1)] then show...

If `A=[(1,1,1),(1,1,1),(1,1,1)]` then show that `A^n=[(3^(n-1),3^(n-1),3^(n-1)),(3^(n-1),3^(n-1),3^(n-1)),(3^(n-1),3^(n-1),3^(n-1))]`.

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