Evaluate `[[sin^2 theta, 1],[cos^2 theta, 0]]+[[cos^2 theta, 0],[-cosec^2 theta, 1]]+[[0,-1],[-1,0]]`

( 1 + cos theta) ( 1 - cos theta ) cosec^2 theta =

The value of (1+ cos theta)(1- cos theta) "cosec"^(2) theta =

(sin theta)/((1+cos theta))+((1+cos theta))/(sin theta)=2cosec theta

If sin theta- cos theta=0 then show that sin^4 theta+cos^4 theta=1/2

(cos^(2)theta)/(sin theta)-cosec theta+sin theta=0

If A= [[cos theta,-sin theta],[sin theta,cos theta]] ,then Adj A is (a) [[cos theta,-sin theta],[cos theta,sin theta]] (b) [[1,0],[0,1]] (c) [[cos theta,sin theta],[-sin theta,cos theta]] (d) [[-1,0],[0,-1]]

((1+cos theta)^2+ sin^2 theta)/ ((cosec^2 theta-1)sin^2 theta) =?

If l cos^2 theta + m sin^2 theta =(cos^2 theta (cosec^2theta +1))/(cosec^2 theta -1), 0^@ lt theta lt 90^@ , then tan theta is equal to

Prove that 1-cos^2theta-sin^2theta=0

If (1/(1+cosec theta ) - 1/(1-cosec theta ))cos theta= 2 , 0^circ lt theta lt 90^circ , then the value of sin^(2) theta + cot^(2) theta + sec^(2) theta is: यदि (1/(1+cosec theta ) - 1/(1-cosec theta ))cos theta= 2 , 0^circ lt theta lt 90^circ , है,तो sin^(2) theta + cot^(2) theta + sec^(2) theta का मान हैः