`[(2x,3)][(1,2),(-3,0)][(x),(3)]=0`

If [ (2x, 3)] [(1,2),(-3,0)][(x),(8)]=0 , find 'x'

Solve the matrix equations: [(x,-5,-1)][(1, 0, 2) ,( 0,2 ,1),( 2, 0, 3)][(x),(4),( 1)]=0 (iv) [2x 3][(1, 2),(-3, 0)][(x),(8)]=0

[[2x,3]][[1,2-3,0]][[x3]]=0

If [(1,x,1)][(1,3,2),(0,5,1),(0,3,2)][(x),(1),(-2)]=[0] then x is

The roots of the equation det [(1-x, 2, 3),(0,2-x,0),(0,2,3-x)]=0 are (A) 1 and 2 (B) 1 and 3 (C) 2 and 3 (D) 1,2, and 3

Let A=[(1,2,3),(2,2,-1),(3,0,k)] and f(x)=x^3-2x^2-alphax+beta=0.If A satisfies f(x)=0, then

For what value of 'x', is the matrix , A=[(0,1,-2),(-1,0,3),(x,-3,0)] a skew - symmetric matrix

If [2x3][[1,2-3,0]][[x3]]=O, find x