If `(n !)/(2!(n-2!))a n d(n !)/(4!(n-4!))` are in the ratio `2:1` , find the value of `ndot`

If (n!)/(2!(n-2!)) and (n!)/(4!(n-4!)) are in the ratio 2:1, find the value of n.

If (n!)/(2!(n-2)!) and (n!)/(4!(n-4)!) are in the ratio 1:2, then n=

IF(n!)/((n-2)!) and (n!)/((n-4)!) are in the ratio 1:12, then n=

If ((2n)!)/(3!(2n-3)!) and (n!)/(2!(n-2)!) are in the ratio 44:3 find n.

I f(n !)/(2!(n-2)!)and(n !)/(4!(n-4)!)a r e i n t h e r a t i o2:1, n!4!(n-4 are in the ratio 2:1, then nn!a) If 21(n -2)1 and

If (n!)/((2!)xx(n-2)!): (n!)/((4!)xx(n-4)!)=2:1 , find the value of n.

(i) If (n!)/(2.(n-2)!): (n!)/(4!.(n-4)!) = 2:1 , find the valye of n. (ii) If ((2n)!)/(3!(2n-3)!): (n!)/(2!(n-2)!) = 44:3 , then find the value of n.

If 25^n^(-1)+100=5^(2n)^(-1), find the value of ndot

.If the numbers n-2,4n-1 and 5n+2 are in A.P. then find the value of n