A library has 5 copies of one book, 4 copies of each of 2 books, 6 copies of ech of 3 books nad single copies of 8 books. In how many ways cn all books be arranged so that copies of the same book are always together?

A library has 6 copies of one book,4 copies of each of two books, 6 copies of each of three books and single copies of 8 books. The number of arrangements of all the books is

If you have 5 copies of one book,4 copies of each of two books,6 copies each of three books and single copy of 8 books you may arrange it in

In how many ways 7 books can be arranged from 10 books?

A library has a copies of one book, b copies each of two books, c copies each of three books, a single copy of d books. The total number of ways in which these books can be arranged in a shelf is equal to a. ((a+2b+3c+d)!)/(a !(b !)^2(c !)^3) b. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^3) c. ((a+b+3c+d)!)/((c !)^3) d. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^)

A library has two books each having three copies and three other books each having tow copies. In how many ways can all these books be arranged in a shelf so that copies of the same book are not separated.