In a set of four numbers, the first three are in GP & the last three are in AP, with common difference 6. If the first number is the same as the fourth, find the four numbers.

In a set of four number, the first three are in GP & the last three are in A.P. with common difference 6. If the first number is the same as the fourth, find the four numbers.

In a set of four numbers, the first three are in GP and the last three are in AP with a common difference of 6. If the number is same as the fourth, then find the four numbers.

In an ordered set of four numbers, the first 3 are A.P. And the last three are in G.P. Whose common ratio is 7//4. If the product of the first and fourth of these numbers is 49, then the product of the second and third of these is :

The first three of four given numbers are in G.P.and their last three are in A.P.with common difference 6. If first and fourth numbers are equal,then the first number is 2 b.4 c.6 d.8

If a, b, c, d be four numbers of which the first three are in AP and the last three are in HP then prove that ad=bc.

Given a sequence of 4 numbers,first,three of which are in G.P.and the last three are in A.P. with common difference six.If first and last terms of this sequence are equal,then:

Out of four numbers, the average of first three is 16 and that of the last three is 15. If, the last number is 18, the first number is: