Evaluate : `sum_(k=1)^n (2^k+3^(k-1))`

sum_(k=1)^n k^3=

Evaluate :sum_(k=1)^(10)(3+2^(k))

Evaluate sum_(k=1)^(11)(2+3^(k))

Evaluate sum_(k=1)^(11)(2+3^(k))

Evaluate : (i) sum_(n=1)^(10)(2+3^(n))" " (ii) sum_(k=1)^(n)[2^(k)+3^((k-1))]" " (iii) sum_(n=1)^(8) 5^(n)

sum_(k =1)^(n) k(1 + 1/n)^(k -1) =

sum_(k=1)^(2n+1)(-1)^(k-1)k^(2)=

If sum_(k=1)^(n)k=45, find the value of sum_(k=1)^(n)k^(3).

If sum_(k=1)^(n)k=210, find the value of sum_(k=1)^(n)k^(2).

Evaluate the sum , sum_(k=1)^(n)(1)/(k(k+1)(k+2)……..(k+r)) .