if `S` is the sum , `P` the product and `R` the sum of reciprocals of `n` terms in `G.P.` prove that `P^2 R^n=S^n`

Let S e the sum,P the product,adn R the sum of reciprocals of n terms in a G.P.Prove that P^(2)R^(n)=S^(n).

Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. then P^2R^3: S^3 is equal to (a)1:1 (b) (common ratio)^n :1 (c)(First term)^2(common ratio)^2 (d) None of these

If S be the sum,p the product and R the sum of the reciprocals of n terms of a G.P.,then ((S)/(R))^(n) is equal to

If S be the sum P the product and R be the sum of the reciprocals of n terms of a GP then p^(2) is equal to S/R b.R/S c.(R/S)^(n) d.(S/R)^(n)

If a be the first term, b be the nth term and P be the product of n terms of a GP then prove that P^2=(ab)^n .

If sum of 3 terms of a G.P. is S product is P ,and sum of reciprocal of its terms is R, then P^(2)R^(3) equals to-

If S_(n) denotes the sum of first n terms of an A.P.prove that S_(12)=3(S_(8)-S_(4))