Find the sum to `n` terms of the series: `1/(1+1^2+1^4)+1/(1+2^2+2^4)+1/(1+3^2+3^4)+`

Find the sum to n terms of the series: (1)/(1+1^(2)+1^(4))+(2)/(1+2^(2)+2^(4))+(3)/(1+3^(2)+3^(4))+

Find the sum to n terms of the series (1)/(1+1^(2)+1^(4))+(2)/(1+2^(2)+2^(4))+(3)/(1+3^(2)+3^(4))+ that means t_(r)=(r)/(r^(4)+r^(2)+1) find sum_(1)^(n)

Find the sum to n terms of the series 1.2.3+2.3.4+3.4.5+…

The sum to n term of the series 1(1!)+2(2!)+3(3!)+

The sum to n term of the series 1(1!)+2(2!)+3(3!)+

Find the sum to n terms of the series: (1)/(1xx2)+(1)/(2xx3)+(1)/(3xx4)+

Find the sum to n terms of the series 1*2^(2)+2*3^(2)+3*4^(2)+...

Find the sum to n terms of the series 1/(1xx2)+1/(2xx3)+1/(3xx4)+...+1/n(n+1)

Find the sum to n terms of the series 1^(2)/(1)+(1^(2)+2^(2))/(1+2)+(1^(2)+2^(2)+3^(2))/(1+2+3)+cdots