If `z_1,z_2,z_3 `be the vertices of an equilateral triangle, show that `1/(z_1-z_2)+1/(z_2-z_3)+1/(z_3-z_1)= 0 or z_1^2+z_2^2+z_3^2= z_1z_2+z_2z_3+z_3z_1`.

If z_(1);z_(2) and z_(3) are the vertices of an equilateral triangle; then (1)/(z_(1)-z_(2))+(1)/(z_(2)-z_(3))+(1)/(z_(3)-z_(1))=0

If A(z_(1)),B(z_(2)), C(z_(3)) are the vertices of an equilateral triangle ABC, then arg (2z_(1)-z_(2)-z_(3))/(z_(3)_z_(2))=

If z_1,z_2,z_3 are vertices of a triangle such that |z_1-z_2|=|z_1-z_3| then arg ((2z_1-z_2-z_3)/(z_3-z_2)) is :

If z_(1),z_(2),z_(3) are the vertices of an equilateral triangle,then value of (z_(2)-z_(3))^(2)+(z_(3)-z_(1))^(2)+(z_(1)-z_(2))^(2)

Complex numbers z_(1),z_(2),z_(3) are the vertices of A,B,C respectively of an equilteral triangle. Show that z_(1)^(2)+z_(2)^(2)+z_(3)^(2)=z_(1)z_(2)+z_(2)z_(3)+z_(3)z_(1).

If z_1, z_2 and z_3 , are the vertices of an equilateral triangle ABC such that |z_1 -i| = |z_2 -i| = |z_3 -i| .then |z_1 +z_2+ z_3| equals to : a) 3sqrt(3) b) sqrt(3) c) 3 d) 1/(3sqrt(3))