The pointo fintersection of the cures represented by the equations `art(z-3i)= (3pi)/4 and arg(2z+1-2i)= pi/4` (A) `3+2i` (B) `- 1/2+5i` (C) `3/4+9/4i` (D) none of these

Find the point of intersection of the curves arg(z-3i)=(3 pi)/(4) and arg (2z+1-2i)=pi/4

The number of points of intersection of the curves represented by arg(z-2-7i)=cot^(-1)(2) and arg ((z-5i)/(z+2-i))=pm pi/2

Find the center of the are represented by arg[(z-3i)/(z-2i+4)]=pi/4

The center of the arc represented by arg [(z-3i)/(z-2i+4)]=(pi)/(4)

The number of values of z satisfying both theequations Arg(z-1-i)=-(3 pi)/(4) and Arg(z-2-2i)=(pi)/(4) is

Number of z, which satisfy Arg(z-3-2i)=(pi)/(6) and Arg(z-3-4i)=(2 pi)/(3) is/are :

How many solutions system of equations, arg (z + 3 -2i) = - pi//4 and |z + 4 | - |z - 3i| = 5 has ?

Let A(z_(1)) be the point of intersection of curves arg(z-2+i)=(3 pi)/(4)) and arg(z+i sqrt(3))=(pi)/(3),B(z_(2)) be the point on the curve ar g(z+i sqrt(3))=(pi)/(3) such that |z_(2)-5|=3 is minimum and C(z_(2)) be the centre of circle |z-5|=3. The area of triangle ABC is equal to

If z= x+iy satisfies the equation arg (z-2)="arg" (2z+3i) , then 3x-4y is equal to

Sketch the region given by (i) Arg (z-1-i)>=(pi)/(3)