`z_1/z_2=` (A) `cos2theta e^(2itheta0` (B) `sec2thetae^-2itheta)` (C) `cos^2thetae^(2itheta)` (D) `sec^2theta e^(-2itheta0`

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z_3^2/(z_1.z_2)= (A) sec^2.cos2theta (B) costheta.sec^22theta (C) cos^2theta.sec2theta (D) sectheta.sec^22theta

(1-cos^2theta)sec^2 theta= tan^2 theta

z_2/z_1 = (A) e^(itheta) cos theta (B) e^(itheta) cos 2theta (C) e^(-itheta) cos theta (D) e^(2itheta) cos 2theta

sec^(2)theta+csc^(2)theta=sec^(2)theta xx cos e^(2)theta

(cos theta-sin theta) / (cos theta + sin theta) = sec2 theta-tan2 theta

Prove :cos ec^(2)theta+sec^(2)theta=cos ec^(2)theta sec^(2)theta

if y=cos^(2)theta+sec^(2)theta then

sec^(2)theta-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta)=1

(cos ec^(2)theta-sec^(2)theta)/(cos ec^(2)theta+sec^(2)theta)=(3)/(4)

Prove that (cos theta-sin theta)/(cos theta+sin theta)=sec2theta-tan2theta