If `|z^2-1|=|z|^2+1` shwo that the locus of z is as straight line.

if |z+1|^(2)+|z|^(2)=4, then the locus of z is

If z=z_(0)+A(bar(z)-(bar(z)_(0))), whereA is a constant,then prove that locus of z is a straight line.

Consider a complex number z=(2w+1)/(iw+1) where w=x+iy if I_(m)(z)=-2 then the locus of omega is a straight line.Find the x- intercept of the line

If z=x+iy, x,y in R such that z!=1 and |z-1|!=1. If (z-1)/(e^((i pi)/(3)))+(e^((i pi)/(3)))/(z-1) is real, then locus of z is a straight line whose slope is

If z be any complex number such that |3z-2|+|3z+2|=4 , then show that locus of z is a line-segment.

If |z^(2)|=2Re(z) then the locus of z is

If z^(2)+z|z|+|z^(2)|=0, then the locus z is a.a a circle b.a straight line c.a pair of straight line d.none of these

if |z-1|=|z-i| then locus of z is