If `z_1,z_2,z_3,z_4` be the vertices of a quadrilaterla taken in order such that `z_1+z_2=z_2+z_3 and |z_1-z_3|=|z_2-z_4|` then arg `((z_1-z_2)/(z_3-z_2))=` (A) `pi/2` (B) `+- pi/2` (C) `pi/3` (D) `pi/6`

If z_1,z_2,z_3 be the vertices of a triangle ABC such that |z_1|=|z_2|=|z_3| and |z_1+z_2|^2= |z_1|^2+|z_2|^2, then |arg, ((z_3-z_1)/(z_3-z_2))|= (A) pi/2 (B) pi/3 (C) pi/6 (D) pi/4

If z_1,z_2,z_3 are vertices of a triangle such that |z_1-z_2|=|z_1-z_3| then arg ((2z_1-z_2-z_3)/(z_3-z_2)) is :

If z_1,z_2,z_3 be the vertices of an equilateral triangle, show that 1/(z_1-z_2)+1/(z_2-z_3)+1/(z_3-z_1)= 0 or z_1^2+z_2^2+z_3^2= z_1z_2+z_2z_3+z_3z_1 .

If z_1,z_2,z_3 be the vertices A,B,C respectively of triangle ABC such that |z_1|=|z_2|=|z_3| and |z_1+z_2|=|z_1-z_2| then C= (A) pi/2 (B) pi/3 (C) pi/6 (D) pi/4

If z_1,z_2,z_3,z_4 be the vertices of a parallelogram taken in anticlockwise direction and |z_1-z_2|=|z_1-z_4|, then sum_(r=1)^4(-1)^r z_r=0 (b) z_1+z_2-z_3-z_4=0 a r g(z_4-z_2)/(z_3-z_1)=pi/2 (d) None of these

If z_(1),z_(2),z_(3),z_(4) are the four complex numbers represented by the vertices of a quadrilateral taken in order such that z_(1)-z_(4)=z_(2)-z_(3) and amp backslash(z_(4)-z_(1))/(z_(2)-z_(1))=(pi)/(2) then the quadrilateral is a

Let A(z_1),B(z_2) and C(z_3) be the vertices of an equilateral triangle in the Argand plane such that |z_1|=|z_2|=|z_3|. Then (A) (z_2+z_3)/(2z_1-z_2-z_3) is purely real (B) (z_2-z_3)/(2z_1-z_2-z_3) is purely imaginary (C) |arg(z_1/z_2)|=2 arg((z_3-z_2)/(z_1-z_2))| (D) none of these