The complex numbers `z_1,=1+2i,z_2=4-2i and z_3=1-6i` form the vertices of a (A) a right angled triangle (B) isosceles triangle (C) equilateral triangle (D) triangle whose one of the sides is of length 8

The points (10, 7, 0), (6, 6,-1) and (6, 9,-4) form a (1) Right-angled triangle (3) Both (1) & (2) (2) Isosceles triangle (4) Equilateral triangle

If z_(1),z_(2),z_(3) are the vertices of an isoscles triangle right angled at z_(2) , then

The complex number z_(1)z_(2)z_(3) are the vertices of a triangle.Then the complex number z which make the triangle into parallelogram is

The complex numbers z_1 z_2 and z3 satisfying (z_1-z_3)/(z_2-z_3) =(1- i sqrt(3))/2 are the vertices of triangle which is (1) of area zero (2) right angled isosceles(3) equilateral (4) obtuse angled isosceles

Let the complex numbers z_1,z_2 and z_3 be the vertices of an equilateral triangle let z_0 be the circumcentre of the triangle. Then prove that z_1^2+z_2^2+z_3^2= 3z_0^2

Complex numbers z_1 , z_2, z_3 are the vertices A, B, C respectively of an isosceles right angled triangle with right angle at C. Show that (z_1-z_2)^2 =2 (z_1 - z_3) (z_3-z_2) .

Let the complex numbers Z_(1), Z_(2) and Z_(3) are the vertices A, B and C respectively of an isosceles right - angled triangle ABC with right angle at C, then the value of ((Z_(1)-Z_(2))^(2))/((Z_(1)-Z_(3))(Z_(3)-Z_(2))) is equal to