If ` x^2-ax+b=0` and ` x^2-px+q=0` have a root in common then the second equation has equal roots show that `b+q=(ap)/2`

If the equations x^(2)-px+q=0 and x^(2)-ax+b=0 have a common root and the second equation has equal roots then

If x^(2)-3x+2=0,3x^(2)+px+q=0 have two roots common then the value of p and q is

If the quadratic equation x^(2)-2x-m=0 and p(q-r)x^(2)-q(r-p)x+r(p-q)=0 have common root such that second equation has equal roots. Then the value of m is

If the equadratic equation 4x ^(2) -2x -m =0 and 4p (q-r) x ^(2) -2p (r-p) x+r (p-q)-=0 have a common root such that second equation has equal roots then the vlaue of m will be :

If the two equation x^(2)-cx+d=0 and x^(2)-ax+b=0 have one common root and the second has equal roots then 2(b + d) is equal to

If x^(2)+ax+b=0 and x^(2)+bx+a=0,(a ne b) have a common root, then a+b is equal to

If the equation x^(2) - 3x + b = 0 and x^(3) - 4x^(2) + qx = 0 , where b ne 0, q ne 0 have one common root and the second equation has two equal roots, then find the value of (q + b) .