The coefficient of x in the equation `x^2+px+q=0` was wrongly written as 17 in place of 13 and the roots thus found were -2 and -15. The roots of the correct equation are (A) `15.-2` (B) `-3,-10` (C) `-13,30` (D) `4,13`

In copying a quadratic equation of the form x^(2)+px+q=0 ,the coefficient of x was wrongly written as -10 in place of -11 and the roots were found to be 4 and 6. find the roots of the correct equation.

Find the coefficients of the equation x^(2)+px+q=0 such that its roots are equal to p and q

[" If the coefficient of "x" in the "],[" quadratic equation "],[x^(2)+px+q=0" was taken as "17],[" in place of "13," its roots were "],[" found to be "-2" and "-15" ,then "],[" the roots of the original "],[" equation are "]

The roots of the equation 4x^(3)-13x^(2)-13x+4=0 is

Find the roots of the equation: x^(2)+13x-48

3+4i is a root of the equation x^(2)+px+q=0 then

If the roots of the equation x^(2)-px+q=0 differ by unity then