If `alpha` and `beta` are the roots of `x^2 +px + q=0` and `alpha^4, beta^4` are the roots of `x^2-rx +s=0`, then the equation `x^2 -4qx+ 2q^2 -r=0` has always

If alpha and beta are the roots of x^(2)+px+q=0and alpha^(4),beta^(4) are the roots of x^(2)-rx+s=0, then the equation x^(2)-4qx+2q^(2)-r=0 has always.A.one positive and one negative root B.two positive roots C.two negative root B.cannot say anything

If alpha and beta are the ral roots of x ^(2) + px +q =0 and alpha ^(4), beta ^(4) are the roots of x ^(2) - rx+s =0. Then the equation x ^(2) -4qx+2q ^(2)-r =0 has always (alpha ne beta, p ne 0 , p,q, r, s in R) :

If alpha,beta are the roots of x^(2)-px+r=0 and alpha+1,beta-1 are the roots of x^(2)-qx+r=0 ,then r is

If alpha and beta are the roots of x^(2)+bx+c=0 and alpha+k and beta+k are the roots of x^(2)+qx+r=0 then k=

If alpha. beta are the roots of x^(2)+bx+c=0 and alpha+h,beta+h are the roots of x^(2)+qx+r=0 then h=

If alpha,beta are the roots of x^2+2x-4=0 and 1/alpha,1/beta are roots of x^2+qx+r=0 then value of -3/(q+r) is