The roots of the equation `ax^2+bx+c=0,a in R^+,` are two consecutive odd positive integers. Then

The roots of the equation a x^2+b x+c=0, a in R^+, are two consecutive odd positive (A) |b|lt=4a (B) |b|geq4a (C) |b|geq2a (D) none of these

If the roots of the cubic x ^(3) +ax ^(2) + bx +c=0 are three consecutive positive integers, then the value of (a ^(2))/(b +1) =

If the roots of the equation x^2-bx+c=0 are two consecutive integers then 3(b^2-4c)=

If the roots of the equation ax^(2)+bx+c=0 are equal then c=?

If the roots of the equation ax^(2)+bx+c=0 are in the ratio m:n then

If the roots of the equation x^(2)-bx+c=0 are two consecutive integers,then find the value of b^(2)-4c.

If the roots of ht cubic,x^(3)+ax^(2)+bx+c=0 are three consecutive positive integers,then the value of (a^(2)/b+1) is equal to

find two consecutive positive odd integers whose sum is 76.

Find two consecutive positive odd integers whose sum is 76.