A square matrix A is invertible iff det (A) is equal to (A) -1 (B) 0 (C) 1 (D) none of these

A square matrix is invertible iff it is non singular

If A is an invertible matrix then det(A^-1) is equal to (A) 1 (B) 1/|A| (C) |A| (D) none of these

If for a square matrix A,A^2=A then |A| is equal to (A) -3 or 3 (B) -2 or 2 (C) 0 or 1 (D) none of these

"If B is a non -singular square matrix of order 3 such that |B|=1 then "det (B^-1) "is equal to (a) 1 (b) 0 (c)-1 (d) none of these"

If A,B and C be the three square matrices such that A=B+C then det A is necessarily equal to (A) detB (B) det C (C) det B+detC (D) none of these

If A is skew symmetric matrix of order 3 then det A is (A)0 (B)-A (C)A (D)none of these

if A is a square matrix such that A^(2)=A, then det (A) is equal to

If A is an invertible matrix of order 2 then det (A^(-1)) is equal to (a) det (A) (b) (1)/(det(A))(c)1 (d) 0

If A is a non singular square matrix then |adj.A| is equal to (A) |A| (B) |A|^(n-2) (C) |A|^(n-1) (D) |A|^n