If A and B are square matrices of the same order then `(A+B)^2=A^2+2AB+B^2` implies (A) `AB=0` (B) `AB+BA=0` (C) `AB=BA` (D) none of these

If A and B are symmetric matrices of the same order then (AB-BA) is always

If A and B are symmetric matrices of same order, then AB - BA is a :

If A, B, and C are three square matrices of the same order, then AB=AC implies B=C . Then

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies (A) both AB and BA are defined (B) (AB)^t=B^tA^t (C) (AB)^-1=B^-1A^-1 if |A|!=0 (D) AB=BA

If A and B are square matices of the same order such that A^2=A,B^2=B,AB=BA=0 then (A) AB^2=0 (B) (A+B)^2=A+B (C) (A-B)^2=A+B (D) none of these

If A and B are square matrices of the same order such that B=-A^(-1)BA, then (A+B)^(2)

If A and B are square matrices of the same order such that AB=A and BA=B ,then (A^(2)+B^(2))=?

If A and B are two square matrices of the same order then (A-B)^2 is (A) A^2-AB-BA+B^2 (B) A^2-2AB+B^2 (C) A^2-2BA+B^2 (D) A^2-B^2