If `A=[(costheta, sin theta),(-sintheta, costheta)]` then `lim_(nrarroo) 1/n A^n` is (A) an identity matrix (B) `[(0,10),(-1,0)]` (C) a null matrix (D) none of these

If {:A=[(costheta,sintheta),(-sintheta,costheta)]:}, " then "lim_(ntooo) 1/nA^n is

If A=[(costheta, sin theta),(-sintheta, costheta)] then lim_(nrarroo) A^n/n is (where theta epsilon R) (A) an idenity matrix (B) a zero matrix (C) [(1,0),(0,1)] (D) [(0,1),(-1,-0)]

(sin3theta-cos3theta)/(sintheta+costheta)+1 =

(sintheta+sin2theta)/(1+costheta+cos2theta) =

(sintheta+sin2theta)/(1+costheta+cos2theta)=?

If A=[(costheta,-sintheta,0),(sintheta,costheta,0),(0,0,1)] , then adj A equals to

If A=[(costheta, -sin theta ),(sin theta, cos theta) ] , then the matrix A^(-50) when theta=pi/12 , is equal to :

If A = [(costheta,-sintheta),(sintheta,costheta)] , then the matrix A^(-50) , when theta = (pi)/(12) , is equal to

If A=[(costheta,sintheta),(-sintheta,costheta)] and A(a d j\ A)=[(k,0),( 0,k)] , then find the value of k .