From the matrix equation `AB=AC` we can conclude that `B=C` provide (A) A is singular (B) A is non singular (C) A is symmetric (D) A is square

From the matrix equation AB = AC we can conclude B = C provided that

From the matrix equation AB=AC, we conclude B=C provided.

If A,B and C are the square matrices of the same order and AB=AC implies B=C, then (A) A is singular (B) A is non-singular (C) A is symmetric (D) A may be any matrix B.

From the matrix equation AB = AC, which one of the following can be concluded ?

A square matrix is invertible iff it is non singular

If A and B are symmetric of the same order, then (A) AB is a symmetric matrix (B) A-B is skew symmetric (C) AB-BA is symmetric matrix (D) AB+BA is a symmetric matrix

Let A and B be two matrices of order n xx n. Let A be non-singular and B be singular. Consider the following : 1. AB is singular 2. AB is non-singular 3. A^(-1) B is singular 4. A^(-1) B is non singular Which of the above is/are correct ?

If the matrix A is both symmetric and skew symmetric,then (A) A is a diagonal matrix (B) A is a zero matrix (C) A is a square matrix (D) None of these

If A is a singular matrix,then adj A is a. singular b.non singular c.symmetric d.not defined