`[(1,3),(3,10)]^-1=` (A) `[(10,3),(3,1)]` (B) `[(10,-3),(-3,1)]` (C) `[(1,3),(3,10)]` (D) `[(-1,-3),(-3,-10)]`

The matrix X in the equation AX=B, such that A= [(1,3),(0,1)] and B= [(1,-1),(0,1)] is given by (A) [(1,0),(-3,1)] (B) [(1,-4),0,1)] (C) [(1,-3),(0,1)] (D) [(0,-1),(-3,1)]

If [(2,1),(3,2)] A[(-3,2),(5,-3)]=[(1,0),(0,1)] then a is equal to (A) [(0,1),(1,1)] (B) [(1,0),(1,1)] (C) [(1,1),(1,0)] (D) [(1,1),(0,1)]

Compute the indicated products (i) [(a,b),(-b,a)][(a,-b),(b,a)] (ii) [(1),(2),(3)]["2 3 4"] (iii) [(1,-2),(2,3)][(1,2,3),(2,3,1)] (iv) [(3,-1,3),(-1,0,2)][(2,-3),(1,0),(3,1)] .

If A=[(2,2),(-3,2)] and B=[(0,-1),(1,0)] then (B^-1A^-1)^-1= (A) [(2,-2),(2,3)] (B) [(3,-2),(2,3)] (C) 1/10 [ (2,2),(-2,3)] (D) 1/10 [(3,-2),(-2,2)]

If A = [(2,3),(1,2)], B = [(1,0),(3,1)] , find AB and (AB)^(-1)

(1""3/(10))^(3)=?

1. (1)/(10)+(3)/(10)+(6)/(10)

If A'=[(-2,3),(1,3)] and B=[(-1,0),(1,2)], find [A+2B]'.