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If bc+qr=ca+rp=ab+pq=-1 and (abc,pqr!=0)...

If `bc+qr=ca+rp=ab+pq=-1` and `(abc,pqr!=0)` then `|[ap,a,p],[bq,b,q],[cr,c,r]|` is (A) 1 (B) 2 (C) 0 (D) 3

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