`a!=p , b!=q,c!=r` and `|(p,b,c),(a,q,c),(a,b,r)|=0` the value of `p/(p-a)+q/(q-b)+r/(r-c)=`

If a!=p,b!=q,c!=r and det[[p,b,ca,q,ca,b,r]]=0, then find the value of (p)/(p-a)+(q)/(q-b)+(r)/(r-c)

a!=p,b!=q,c!=r and det[[p,b,ca,q,ca,q,ca,b,r]] value of (p)/(p-a)+(q)/(q-b)+(r)/(r-c),=

If det[[p,b,ca,q,ca,b,r]]=0, find the value of (p)/(p-a)+(q)/(q-b)+(r)/(r-c),p!=a,q!=b,r!=c

If a,b,cp,q,r six complex numbers such that (p)/(a)+(q)/(b)+(r)/(c)=1+i and (a)/(p)+(b)/(q)+(c)/(r)=0 then value of (p^(2))/(a^(2))+(q^(2))/(b^(2))+(r^(2))/(c^(2))=

Given A=[[p,b,ca,q,ca,b,r]]. If det(A)=0 and a!=p,b!=q,c!=q, then prove p-a,+(q)/(q-b)+(r)/(r-c)=2

If A = |(a,b,c),(x,y,z),(p,q,r)| and B = |(q,-b,y),(-p,a,-x),(r,-c,z)| , then