Choose any 9 distinct integers. These 9 ...

Choose any 9 distinct integers. These 9 integers cn be arrnanged to form 9! Determinants each of order 3. Then sum of these 9! Determinants is (A) 0 (B) 3! (C) lt0 (D) 9!

Similar Questions

Explore conceptually related problems

If A is a square matrix of order 3 and |A|=3 then |adjA| is (A) 3 ; (B) 9 ; (C) (1)/(3) ; (D) 0

The sum of two consecutive integers is 9. Find the smallest integer.

B takes the value 0 (b) 5 (c) 9 (d) 0 or 9

Determine (8x)^(x), if 9^(x+2)=240+9^(x)

The sum of two integers is -11. If one of them is 9, find the other.

If the product of two integers is 72 and one of them is -9 , then the other integer is (a) -8 (b) 8 (c) 81 (d) 63

The number of pair of positive integers whose sum is 99 and HCF is 9 is (a) 5 (b) 4 (c) 3 (d) 2

Determine wheater there is a perfect square that ends in 9 distinct digits.

If A is a square matrix of order 2, then det(-3A) is A) 3 det A B) -3 det A C) 9 det A D) -9 det A