If a,b,c are in G.P. then the value of `|(a,b,a+b),(b,c,b+c),(a+b,b+c,0)|=` (A) 1 (B) -1 (C) `a+b+c` (D) 0

If a,b,c,d are in G.P., then the value of (a-c)^2+(b-c)^2+(b-d)^2-(a-d)^2 is (A) 0 (B) 1 (C) a+d (D) a-d

If a,b,c are in G.P then (b-a)/(b-c)+(b+a)/(b+c)=

If a,b, and c are in G.P then a+b,2b and b+ c are in

If a b c=0 , then find the value of {(x^a)^b}^c (a)1 (b) a (c)b (d) c

If a b+b c+c a=0 , then what is the value of (1/(a^2-b c)+1/(b^2-c a)+1/(c^2-a b)) ? (a) 0 (b) 1 (c) 3 (d) a+b+c

If a,b,(c+1) are in G.P.and a=(b-c)^(2) then a,b,c are in