The value of the determinant `|(1+a, 1, 1),(1, 1+a, 1),(1, 1, 1+a)|` is zero if (A) `a=-3` (B) `a=0` (C) `a=2` (D) `a=1`

If the value of the determinant |{:(a,1,1),(1,b,1),(1,1,c):}| is positive then

The value of the determinant |{:(1,0,-1),(a,1,1-a),(b,a,1+a-b):}| depends on :

if the value of the determinant |{:(a,,1,,1),(1,,b,,1),(1,,1,,c):}| is positivie then (a,b,c lt 0)

" 0.The value of the determinant "|[1,x,x^(2)],[1,b,b^(2)],[1,c,c^(2)]|" is: "

The value of the determinant |{:(1,a, a^(2)-bc),(1, b, b^(2)-ca),(1, c, c^(2)-ab):}| is…..

The least value of the product xyz for which the determinant |(x,1,1),(1,y,1),(1,1,z)| is non-negative, is: (A) -16sqrt2 (B) -2sqrt2 (C) -1 (D) -8

If the value of the determinant |(a,1,1),(1,b,1),(1,1,c)| is positive, where a ne be ne c , then the value of abc.

If the value of the determinant |a1 1 1b1 1 1c| is positive then (a ,b ,c >0) a b c >1 b. a b c -2

If C = 2 cos theta , then the value of the determinant Delta = |(C,1,0),(1,C,1),(6,1,c)| , is