m women and n men are too be seated in a row so that no two men sit together. If `mgtn` then show that the number of wys in which they can be seated is `(m!(m+1)!)/((m-n+1)!)`

m men and n women are to be seated in a row so that no two women sit together.If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!)

m men and w women are to be seated in a row so that no two women sit together.If m>w then the number of ways in which they can be seated is

5 men and 6 women have to be seated in a straight row so that no two women are together. Find the number of ways this can be done.

If m red balls and n white balls are placed in a row so that no two white balls are together, prove that if m gt n , the total number of ways in which this can be done is ""^(m+1)C_(n) .