The number of divisors of the form `(4n+2)` of the integer 240 is

The number of divisors of the form 4K + 2 , K ge 0 of the integers 240 is

Let n be a non - negative integer . Then the number of divisors of the form '' 4n + 1'' of the number (10)^(10)*(11)^(11)*(13)^(13) is equal to _____

If N=10800, find the ( i ) the number of divisors of the form 4m+2, (ii) the number of divisors which are multiple of 10(iii) the number of divisors which are multiple of 15.

If n=10800, then find the a. total number of divisors of n. (b) The numberof even divisors. (c) The number of divisors of the form 4m+2. (d) The number of divisors which are multiples of 15.