The number of zeros at the end of (108!) is (A) 25 (B) 16 (C) 21 (D) 10

The number of zeros at the end of 60! is 12 (b) 14(c)16 (d) 18

The number of zeros at the end of 5^(10)! is (a^(10)-1)/(b) then a+b is

The numbers 1, 3, 5, ….. 25 are multiplied together. The number of zeros at the right end of the product is 0 (b) 1 (c) 2 (d) 3

First 100 multiples of 10 i.e.10,20,30,...1000 are multiplied together.The number of zeros at the end of the product will be 100 (b) 111 (c) 124 (d) 125

The numbers 2,4,6,8,.....98,100 are multiplied together.The number of zeros at the end of the product must be 10 (b) 11 (c) 12 (d) 13

The product of all integers from 1 to 100 will have the following number of zeros at the end: (a)20 (b)21 (c)19 (d)24

The number 25^(64)xx64^(25) is the square of a natural number n. The sum of the digits of n is (a) 7 (b) 14 (c) 21 (d) 28