The number of factors (excluding 1 and the expression itself) of the product of `a^(7)b^(4)c^(3)` def, where a, b, c, d, e, fare all prime numbers, is

A number is said to be a nice number if it has exactly 4 factors (includng 1 and the number itself). Then number of divisor of 2520 which are nice numbers is (A) 7 (B) 8 (C) 9 (D) none of these

The number of prime factors in the expression 6^(10)*7^(17)backslash11^(27) is equal to 54 (b) 64 (c) 71 (d) 81

Let (a)/(b)=(c)/(d) (where a and bare odd prime numbers),It c>a and d>b, then:

Find the number of ways of expressing 10 as a product of co-prime factors.

If the numbers a, b, c, d, e are in arithmetic progression then find the value of a - 4b + 6c - 4d + e.

If the value of sin9^(@) is expressed in the form of (sqrt(a+sqrt(c))-sqrt(c-sqrt(c)))/(b) , where a,b,c are co- prime natural numbers then find a, b and c

Find the number of ways of expressing 49 as a product of co-prime factors.