If the sum of `m` terms of an `A.P` is equal to these that `n` terms and also to the sum of the next `p` terms, prove `(m+n)(1/m - 1/p) =(m+p)(1/m-1/n)`

If the sum of m terms of an A.P.is equal to the sum of either the next n terms or the next p terms,then prove that (m+n)((1)/(m)-(1)/(p))=(m+p)((1)/(m)-(1)/(n))

If the sum of m terms of an A.P. is same as the sum of its n terms, then the sum of its (m+n) terms is

If the sum of m terms of an AP is the same as the sum of its n terms , show that the sum of its (m+n) terms is zero .

If m times the mth term of an A.P. is equal to n times its nth term, find (m + n) th term of the A.P.:

If the sum of n terms of an A.P. is 3n^(2)+5n and its mth term is 164, find the value of m.

If the sum of n terms of an A.P is cn (n-1)where c ne 0 then the sum of the squares of these terms is

if the sum of m terms of an A.P is to the sum of n terms as m^(2) to n^(2) show that the mth term is to the n th term as 2m-1 to 2n-1