The three digit number whose digits are in G.P. and the digits of the number obtained from it by subtracting 400 form an A.P. is equal to.

Find a three – digit number such that its digits are in increasing G.P. (from left to right) and the digits of the number obtained from it by subtracting 100 form an A.P.

Find a three digit number if its digits form a geometric progression and the digits of the number which is smallar by 400 form an A.P. is

The digits of a three digit number are in G.P. when the digits of this number are reversed and this resultant number is subtracted from the original number the difference comes out to be 792. The actual number is:

The digits of a three digit number N are in A.P. If sum of the digit is 15 and the number obtained by re-versing the digits of the number is 594 less than the original number, then (1000)/(N-252) is equal to

G={x:x is two digit number sum of whose digits is 4}

The hundred digit of a three digit number is 7 more than the unit digit. The digits of the number are reversed and the resulting number is subtracted from the original three digit number. The unit digit of the final number, so obtained is

Find a three digit number whose consecutive digits form a G.P. if we subtract 792 from this number, we get a number consisting of the same digits written in the reverse order. Now, it we increase the second digit of the required number by 2, then the resulting digits will form an A.P.