If `9A.M.'s` and `9 H.M's` be inserted between `2` and `3` and `A` be any `A.M.` and `H` be the corresponding `H.M.,` then `H(5-A)`

If 9A.M.'s and 9H.M's be inserted between 2 and 3 and A be any A.M. and H be the corresponding H.M., then H(5-A)

In S.H.M.,

In S.H.M

Insert 20 A.M. between 2 and 86.

m A.M. and 3 G.M. are inserted between 3 and 243 such that 2^(nd) GM= 4^(th) AM then m=

If nine arithmetic means and nine harmonic means are inserted between 2 and 3 alternatively,then prove that A+6/H=5 (where A is any of the A.M.'s and H the corresponding H.M.).

If eleven A.M.s are inserted between 28 and 10, then find the number of integral A.M.s .

Insert four H.M.s between 2/3 and 2/13