A triangle `PQR , /_R=90^@` and `tan(P/2)` and `tan(Q/2)` roots of the `ax^2+bx+c=0` then prove that `a+b=c`

In a Delta PQR, /_R=(pi)/(2) .if tan(P/2) and tan(Q/2) are the roots of the equation ax^(2)+bx+c=0 ,then relation between a, b and c

In a triangle PQR, angleR = pi //2 . If tan (P/2) and tan (Q/2) are the roots of the equations ax^(2) + bx + c = 0 where a ne 0 , then

If, in a /_\PQR , right angled at R, tan (P/2) and tan (Q/2) are the roots of the equation ax^(2) + bx + c = 0 , a!= 0 , then

If /_\ PQR is right-angled at R and tan P/2, tan Q/2 are the roots of the equation ax^(2) + bx + c = 0, a != 0 , show that a + b = c .

If tan theta and sec theta are the roots of ax^(2)+bx+c=0, then prove that a^(4)=b^(2)(b^(2)-4ac)

If sin theta,cos theta be the roots of ax^(2)+bx+c=0, then prove that b^(2)=a^(2)+2ac.