Let `A=[5 5alphaalpha0alpha5alpha0 0 5]dot"I f"|A^2|=25 ,` then `|alpha|` equals (1) `5^2` (2) 1 (3) 1/5 (4) 5

Let A=[[5,5 alpha,alpha0,alpha,5 alpha0,0,5]].IfA^(2)=25, then alpha

Let A=[[5,5 alpha,alpha],[0,alpha,5 alpha],[0,0,5]] .If |A^(2)|=25 ,then | alpha| equals

Let A=[(5,5alpha,alpha),(0,alpha,5alpha),(0,0,5)] . If |A|^2=25 , then |alpha| is equal to :

Prove that |1alphaalpha^2alphaalpha^2 1alpha^2 1alpha|=-(1-alpha^3)^2dot

If alpha,beta are the roots of x^(2)-x+1=0, then alpha^(5)+beta^(5) is

If alpha,beta are the roots of x^(2)-2x+4=0 then alpha^(5)+beta^(5)=

Let cos(alpha+beta)""=4/5 and let s in(alphabeta)""=5/(13) where 0lt=alpha,betalt=pi/4 , then t a n""2alpha= (1) (56)/(33) (2) (19)/(12) (3) (20)/7 (4) (25)/(16)

If 5sin alpha=3(alpha+2 beta)!=0, then tan(alpha+beta) is equal to