If `x` is so small that `x^3` and higher powers of `x` may be neglectd, then `((1+x)^(3//2)-(1+1/2x)^3)/((1-x)^(1//2))` may be approximated as `3x+3/8x^2` b. `1-3/8x^2` c. `x/2-3/xx^2` d. `-3/8x^2`

If x is so small that x^(3) and higher powers of x may be neglected, then ((1+x)^(3//2)-(1+1/2 x)^3)/((1-x)^(1//2)) may be approximated as

If x is so small that x^(3) and higher powers of x may be neglectd,then ((1+x)^(3/2)-(1+(1)/(2)x)^(3))/((1-x)^(1/2)) may be approximated as 3x+(3)/(8)x^(2) b.1-(3)/(8)x^(2) c.(x)/(2)-(3)/(x)x^(2) d.-(3)/(8)x^(2)

If x is small so that x^(2) and higher powers can be neglected,then the approximate value for ((1-2x)^(-1)(1-3x)^(-2))/((1-4x)^(-3)) is

If x is so small such that its square and higher powers may be neglected then find the approximate value of ((1-3x)^(1//2)+(1-x)^(5//3))/((4+x)^(1//2))

If |x| is so small that x^(2) and higher power of x may be neglected then the approximate value of ((4+x)^((1)/(2))+(8-x)^((1)/(3)))/((1-(2x)/(3))^((3)/(2))) when x=(6)/(25) is

Assuming x to be so small that x^(2) and higher power of x can be neglected,prove that ((1+(3x)/(4))^(-4)(16-3x)^((1)/(2)))/((8+x)^((2)/(3)))=1-((305)/(96))x