If `A (1, 5), B (-2, 1) and C (4, 1)` be the vertices of `DeltaABC` and internal bisector of `/_A` meets `BC` at `D`, find `AD`.

If A(4, 2), B(6, 5) and C(1, 4) be the vertices of Delta ABC and AD is a median, then the coordinates of D are

If A ( 2,2,-3) B ( 5,6,9) ,C (2,7,9) be the vertices of a triangle. The internal bisector of the angle A meets BC at the point D, then find the coordinates of D.

If A(3,1,-1),B(4,-1,1),C(5,2,1) be the vertices of a Delta ABC then the length of the internal bisector of angle A is

A(-1,2,-3),B(5,0,-6) and C(0,4,-7) are the vertices of a triangle.The DRs of the internal bisector of /_BAC are

If A(1, 4), B(2, -3) and C (-1, -2) are the vertices of a DeltaABC . Find (i) the equation of the median through A (ii) the equation of the altitude through A. (iii) the right bisector of the side BC .

If A(1,-1,3),B(2,1,-2),C(-5,2-6) are the vertices of a /_ABC ,then the lengh of internal bisector of angle A is

7. Let A (4, 2) B(6.,5) and C(1.,4). be the vertices of DeltaABC. (1) The median from A meets BC at D. Find the coordinates of the point D. (2) the coordinates of the point P on AD such that AP: PD= 2:1. (3) Find the coordinates of points Q and R on medians BE and CF respectively such that BQ: QE = 2 :1 and CR :RF =2: 1. (4) what do yo observe?

Let A(1, 2, 3), B(0, 0, 1) and C(-1, 1, 1) are the vertices of triangleABC . Q. The equation of internal angle bisector through A to side BC is

The vertices of a triangle are A(5,4,6),B(1,-1,3) and (4,3,2) . The internal bisector of /_BAC meets BC in D. Find AD.