One end of a diameterof a circle is at `(2, 3)` and the centre is `(-2, 5)`, find the coordinates of the other end of the diameter.

If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (-2,5), then the coordinates of the other end of the diameter are

If the coordinates of one end of a diameter of a circle are (2,3) and the coordinates of its centre are (-2,5), then the coordinates of the other end of the diameter are (-6,7) (b) (6,-7)( c) (6,7)(d)(-6,-7)

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.

The coordinates of one end of a diameter of a circle are (5, -7) . If the coordinates of the centre be (7, 3) find the coordinates of the other end of the diameter.

A circle, has its centre at (-1, 3). If one end of a diameter of the circle has co-ordinates (2,5), then find the co-ordinates of the other end of the diameter.

A circle, has its centre at (-1, 3). If one end of a diameter of the circle has co-ordinates (2,5), then find the co-ordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2)+y^(2)-4x-6y+11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

One end of the diameter of a circle with the centre as origin is (-2 ,10) . Find the other end of the diameter