A and B are two given points whose coordinates are `(-5, 3) and (2, 4)` respectively. A point P moves in such a manner that `PA : PB = 3:2`. Find the equation to the locus traed out by `P`.

A and B are two given points whose co- ordinates are (-5,3) and (2,4) respectively. A point P moves in such a manner that PA:PB=3:2. Find the equation to the locus traced out by P.

If A and B are two points having coordinates (-2,-2) and (2,-4) respectively,find the coordinates of P such that AP=(3)/(7)AB

A and B are two fixed points whose coordinates (3,2) and (5,4) respectively.The coordinates of a poin if ABP is an equilateral triangle,are

The coordinates of the point A and B are (a,0) and (-a,0), respectively.If a point P moves so that PA^(2)-PB^(2)=2k^(2), when k is constant,then find the equation to the locus of the point P.

A(1,2) , B(2,-3) And C(-2,3) are three points. A point P moves such that PA^(2)+PB^(2)=2PC^(2) .Show that the equation to the locus of P is 7x-7y+4=0

A variable line through the point ((6)/(5),(6)/(5)) cuts the coordinate axes at the points A and B respectively. If the point P divides AB internally in the ratio 2:1 , then the equation of the locus of P is

Coordinates of the points A, B, C,D are (13,7), (-5,2), (7,3) and (3,7) respectively. Let AB and CD meet at P, then PA:PB is equal to

If A(3,0), B(-3,0) and PA+PB=10 then the equation of the locus of P is

If the coordinates of points A and B are (-2, -2) and (2, -4) respectively, find the coordinates of the point P such that AP = (3)/(7)AB , where P lies on the line segment AB.