The angle between the diagonals of a quadrilateral formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2 and x/b+y/a=2` is

Prove that the diagonals of the parallelogram formed by the lines x/a +y/b=1,x/b+y/a= 1, x/a + y/b = 2 and x/b + y/a = 2 are at right angles . Also find its area (a != b)

The equation of the diagonal through origin of the quadrilateral formed by the lines x=0,y=0,x+y-1=0 and 6x+y-3=0, is

If b gt a , d gt c then are of quadrilateral formed by straight lines x = b, x = a, y = c and y =d is

Prove that the diagonals of the parallelogram formed by the four lines : (x)/(a)+(y)/(b)=1 , (x)/(a)+(y)/(b)=-1 , (x)/(a)-(y)/(b)=1 , (x)/(a)-(y)/(b)=-1 are at right angles.

Prove that the parallelogram formed by the straight lines : (x)/(a)+(y)/(b)=1 , (x)/(b)+(y)/(a)=1 , (x)/(a)+(y)/(b)=2 and (x)/(b)+(y)/(a)=2 is a rhombus.

Show that the tangent of an angle between the lines x/a+y/b=1 and x/b-y/b=1\ i s(2a b)/(a^2-b^2)

The length of the perpendicular form the point (b,a) to the line x/a-y/b =1 is